(7x-5)(x^2-5x-1)=0

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Solution for (7x-5)(x^2-5x-1)=0 equation: 


Simplifying
(7x + -5)(x2 + -5x + -1) = 0

Reorder the terms:
(-5 + 7x)(x2 + -5x + -1) = 0

Reorder the terms:
(-5 + 7x)(-1 + -5x + x2) = 0

Multiply (-5 + 7x) * (-1 + -5x + x2)
(-5(-1 + -5x + x2) + 7x * (-1 + -5x + x2)) = 0
((-1 * -5 + -5x * -5 + x2 * -5) + 7x * (-1 + -5x + x2)) = 0
((5 + 25x + -5x2) + 7x * (-1 + -5x + x2)) = 0
(5 + 25x + -5x2 + (-1 * 7x + -5x * 7x + x2 * 7x)) = 0
(5 + 25x + -5x2 + (-7x + -35x2 + 7x3)) = 0

Reorder the terms:
(5 + 25x + -7x + -5x2 + -35x2 + 7x3) = 0

Combine like terms: 25x + -7x = 18x
(5 + 18x + -5x2 + -35x2 + 7x3) = 0

Combine like terms: -5x2 + -35x2 = -40x2
(5 + 18x + -40x2 + 7x3) = 0

Solving
5 + 18x + -40x2 + 7x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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